EduSahara™ Assignment
Name : Rationalizing Factor
Chapter : Real Numbers
Grade : SSC Grade IX
License : Non Commercial Use
Question
1
1.
The rationalising factor of
(
−
9
√
77
)
=
(i)
√
79
(ii)
4
√
77
(iii)
√
74
(iv)
√
77
(v)
77
Question
2
2.
Rationalise the denominator of
1
(
−
7
√
7
)
(i)
(
−
1
49
√
9
)
(ii)
(
−
1
7
)
(iii)
(
−
1
49
4
√
7
)
(iv)
(
−
1
49
√
5
)
(v)
(
−
1
49
√
7
)
Question
3
3.
Rationalise the denominator of
1
(
√
3
−
√
2
)
(i)
(
√
3
+
2
)
(ii)
(
√
3
+
√
2
)
(iii)
(
√
1
3
+
√
2
)
(iv)
(
√
3
+
4
√
2
)
(v)
(
√
5
+
√
2
)
Question
4
4.
Rationalise the denominator of
1
(
16
√
2
+
8
√
3
)
(i)
(
1
20
√
5
−
1
40
√
3
)
(ii)
(
1
20
√
2
−
3
40
)
(iii)
(
1
20
√
-1
−
1
40
√
3
)
(iv)
(
1
20
√
2
−
1
40
4
√
3
)
(v)
(
1
20
√
2
−
1
40
√
3
)
Question
5
5.
Rationalise the denominator of
1
(
√
4
+
√
2
+
√
3
)
(i)
(
2
23
+
5
23
√
2
+
3
23
4
√
3
−
4
23
√
6
)
(ii)
(
2
23
+
5
23
4
√
2
+
3
23
√
3
−
4
23
√
6
)
(iii)
(
2
23
+
5
23
√
2
+
3
23
√
3
−
4
23
√
6
)
(iv)
(
0
+
5
23
√
2
+
3
23
√
3
−
4
23
√
6
)
(v)
(
2
23
+
5
23
√
2
+
3
23
√
3
−
4
23
√
8
)
Question
6
6.
Rationalise the denominator of
1
(
2
√
3
+
√
5
+
5
√
2
)
(i)
(
−
86
849
√
3
−
19
283
√
5
+
55
283
√
2
+
20
849
√
33
)
(ii)
(
−
86
849
−
19
283
√
5
+
55
283
√
2
+
20
849
√
30
)
(iii)
(
−
86
849
√
3
−
19
283
4
√
5
+
55
283
√
2
+
20
849
√
30
)
(iv)
(
−
86
849
√
3
−
19
283
√
5
+
55
283
√
2
+
20
849
√
30
)
(v)
(
−
86
849
√
3
−
19
283
√
5
+
55
283
4
√
2
+
20
849
√
30
)
Question
7
7.
Rationalise the denominator of
1
(
3
√
4
−
3
√
3
)
(i)
(
2
3
√
2
+
3
√
12
+
3
√
9
)
(ii)
(
2
3
√
2
+
3
√
12
+
9
)
(iii)
(
2
3
√
2
+
3
√
12
+
5
√
9
)
(iv)
(
2
3
√
2
+
3
√
10
+
3
√
9
)
(v)
(
2
3
√
2
+
3
√
14
+
3
√
9
)
Question
8
8.
Rationalise the denominator of
(
−
√
2
+
√
6
)
(
√
7
−
√
5
)
=
(i)
(
−
1
2
√
14
+
1
2
√
42
−
1
2
√
10
+
1
2
√
33
)
(ii)
(
−
1
2
√
14
+
1
2
√
42
−
1
2
√
10
+
1
2
√
30
)
(iii)
(
−
1
2
√
14
+
1
2
4
√
42
−
1
2
√
10
+
1
2
√
30
)
(iv)
(
−
1
2
√
12
+
1
2
√
42
−
1
2
√
10
+
1
2
√
30
)
(v)
(
−
1
2
√
14
+
1
2
√
42
−
1
2
4
√
10
+
1
2
√
30
)
Question
9
9.
Rationalise the denominator of
(
−
6
√
2
−
4
√
9
)
(
12
+
3
√
3
)
=
(i)
(
−
8
13
√
2
−
16
13
+
2
13
4
√
6
+
4
13
√
3
)
(ii)
(
−
8
13
√
-1
−
16
13
+
2
13
√
6
+
4
13
√
3
)
(iii)
(
−
8
13
√
2
−
16
13
+
2
13
√
6
+
4
13
√
6
)
(iv)
(
−
8
13
√
2
−
16
13
+
2
13
√
6
+
4
13
√
3
)
(v)
(
−
8
13
√
2
−
6
5
+
2
13
√
6
+
4
13
√
3
)
Assignment Key
1) (iv)
2) (v)
3) (ii)
4) (v)
5) (iii)
6) (iv)
7) (i)
8) (ii)
9) (iv)
