EduSahara™ Assignment
Name : Finding Quadratic Equations when Roots are given
Chapter : Quadratic Equations
Grade : ICSE Grade X
License : Non Commercial Use
Question
1
1.
Find the quadratic equation with roots
(
1
4
,
1
4
)
(i)
(
16
x
2
−
8
x
+
1
)
=
0
(ii)
(
16
x
2
−
16
x
+
3
)
=
0
(iii)
(
16
x
2
−
1
)
=
0
(iv)
(
8
x
2
−
6
x
+
1
)
=
0
(v)
(
24
x
2
−
10
x
+
1
)
=
0
Question
2
2.
Find the quadratic equation with roots
(
(
-1
3
)
,
9
5
)
(i)
(
21
x
2
−
20
x
−
9
)
=
0
(ii)
(
15
x
2
−
28
x
−
11
)
=
0
(iii)
(
15
x
2
−
22
x
−
9
)
=
0
(iv)
(
5
x
2
−
4
x
−
9
)
=
0
Question
3
3.
Find the quadratic equation with roots
(
-2
,
-2
)
(i)
(
x
2
+
3
x
+
2
)
=
0
(ii)
(
x
2
+
4
x
+
4
)
=
0
(iii)
(
x
2
+
6
x
+
8
)
=
0
(iv)
(
x
2
+
5
x
+
6
)
=
0
(v)
(
x
2
+
x
−
2
)
=
0
Question
4
4.
Find the quadratic equation with roots
(
-2
,
4
)
(i)
(
x
2
−
5
x
−
14
)
=
0
(ii)
(
x
2
−
3
x
−
10
)
=
0
(iii)
(
x
2
−
16
)
=
0
(iv)
(
x
2
−
x
−
12
)
=
0
(v)
(
x
2
−
2
x
−
8
)
=
0
Question
5
5.
Find the quadratic equation, the sum of whose roots is
6
and product is
9
(i)
(
x
2
−
6
x
+
9
)
=
0
(ii)
(
−
6
x
+
9
)
=
0
(iii)
(
2
x
2
−
6
x
+
9
)
=
0
(iv)
(
x
2
−
8
x
+
9
)
=
0
(v)
(
x
2
−
4
x
+
9
)
=
0
Question
6
6.
Find the quadratic equation, the sum of whose roots is
5
and product is
-14
(i)
(
x
2
−
5
x
−
14
)
=
0
(ii)
(
x
2
−
3
x
−
14
)
=
0
(iii)
(
x
2
−
7
x
−
14
)
=
0
(iv)
(
2
x
2
−
5
x
−
14
)
=
0
(v)
(
−
5
x
−
14
)
=
0
Question
7
7.
Find the quadratic equation, the sum of whose roots is
(
-4
3
)
and product is
4
9
(i)
(
9
x
2
+
12
x
+
4
)
=
0
(ii)
(
9
x
2
+
15
x
+
4
)
=
0
(iii)
(
8
x
2
+
12
x
+
4
)
=
0
(iv)
(
9
x
2
+
9
x
+
4
)
=
0
(v)
(
10
x
2
+
12
x
+
4
)
=
0
Question
8
8.
Find the quadratic equation, the sum of whose roots is
(
-12
7
)
and product is
(
-4
7
)
(i)
(
14
x
2
+
27
x
−
8
)
=
0
(ii)
(
14
x
2
+
24
x
−
8
)
=
0
(iii)
(
15
x
2
+
24
x
−
8
)
=
0
(iv)
(
14
x
2
+
21
x
−
8
)
=
0
(v)
(
13
x
2
+
24
x
−
8
)
=
0
Question
9
9.
Find the quadratic equation whose roots are
(
1
−
5
√
5
)
and
(
1
+
5
√
5
)
(i)
(
x
2
+
x
−
124
)
=
0
(ii)
(
x
2
−
4
x
−
124
)
=
0
(iii)
(
2
x
2
−
2
x
−
124
)
=
0
(iv)
(
x
2
−
2
x
−
124
)
=
0
(v)
(
−
2
x
−
124
)
=
0
Assignment Key
1) (i)
2) (iii)
3) (ii)
4) (v)
5) (i)
6) (i)
7) (i)
8) (ii)
9) (iv)