ICSE Board Practice

ICSE Grade VIII - Perimeter and Area of Plane Figures
Question 1
1.
If the outer radius of the ring is 9.00 cm and area of the ring is 53.43 sq.cm, the width of the ring is
  • 9.00 cm
  • 0.00 cm
  • 2.00 cm
  • 3.00 cm
  • 1.00 cm
Question 2
2.
Find the perimeter of the shaded region given below
  • 152.00 m
  • 166.00 m
  • 140.00 m
  • 178.00 m
  • 183.00 m
Question 3
3.
If height of an equilateral triangle is 17.32 cm, the side of the equilateral triangle =
  • 23.00 cm
  • 20.00 cm
  • 15.00 cm
  • 25.00 cm
  • 17.00 cm
Question 4
4.
In the given figure, arcs of two concentric circles of radii 13.00 cm and 5.20 cm are drawn with center O. If ∠LOM = 90°, find the area of the shaded region
  • 116.54 sq.cm
  • 88.54 sq.cm
  • 135.54 sq.cm
  • 99.54 sq.cm
  • 111.54 sq.cm
Question 5
5.
In the given figure ,PQRS is the diameter of the circle of radius 1.50 cm and PQ = QR = RS. Find the area of the shaded region
  • 2.71 sq.cm
  • 6.71 sq.cm
  • 4.71 sq.cm
  • 3.71 sq.cm
  • 5.71 sq.cm
Question 6
6.
If the breadth and perimeter of a rectangle are 5.00 cm and 26.00 cm respectively, the length of the rectangle =
  • 6.00 cm
  • 8.00 cm
  • 7.00 cm
  • 9.00 cm
  • 10.00 cm
Question 7
7.
In the given figure, the triangle inside the square is an isosceles triangle. Find the area of the shaded region
  • 57.50 sq.cm
  • 65.50 sq.cm
  • 55.50 sq.cm
  • 63.50 sq.cm
  • 60.50 sq.cm
Question 8
8.
In a right angled triangle △PQR, if the base QR = 20 cm and the corresponding height is 17 cm, then area of the triangle =
  • 170.00 sq.cm
  • 153.00 sq.cm
  • 158.00 sq.cm
  • 194.00 sq.cm
  • 183.00 sq.cm
Question 9
9.
    • A rectangular field is 42 m by 25 m. It has two paths through its centre, running parallel to its sides.
    • The width of the longer and the shorter paths are 9 m and 16 m respectively.
    • Find the total expense involved in laying tiles on the paths at ₹20.6 per 1 sq.m and laying grass in the remaining portion at ₹17.3 per 1 sq.m.
  • ₹20256.20
  • ₹20255.20
  • ₹20257.20
  • ₹20259.20
  • ₹20258.20
Question 10
10.
In an isosceles triangle △ABC, if base BC = 20 cm and the corresponding height is 11.18 cm, then corresponding height of side CA =
  • 9.91 cm
  • 11.91 cm
  • 19.91 cm
  • 14.91 cm
  • 17.91 cm