ICSE Board Practice

ICSE Grade VIII - Perimeter and Area of Plane Figures
Question 1
1.
If the length and diagonal of a rectangle are 15.00 cm and 16.55 cm respectively, the perimeter of the rectangle =
  • 49.00 cm
  • 39.00 cm
  • 44.00 cm
  • 47.00 cm
  • 41.00 cm
Question 2
2.
If the area of the inner circle of the ring is 78.57 sq.cm and area of outer circle is 154.00 sq.cm, the area of the ring is
  • 78.43 sq.cm
  • 70.43 sq.cm
  • 80.43 sq.cm
  • 72.43 sq.cm
  • 75.43 sq.cm
Question 3
3.
In the given figure, ABCD is a square with side 13.00 cm. Find the area of the shaded region
  • 93.57 sq.cm
  • 96.57 sq.cm
  • 101.57 sq.cm
  • 91.57 sq.cm
  • 99.57 sq.cm
Question 4
4.
Find the perimeter of the shaded region given below
  • 154.00 m
  • 128.00 m
  • 142.00 m
  • 106.00 m
  • 121.00 m
Question 5
5.
Find the area of the shaded region in the given figure common between the two quadrants of circles of radius 16.00 cm each
  • 146.29 sq.cm
  • 151.29 sq.cm
  • 119.29 sq.cm
  • 168.29 sq.cm
  • 132.29 sq.cm
Question 6
6.
In an isosceles right angled triangle △PQR, if QR = 18 cm is one of the equal sides, then perimeter of the triangle =
  • 58.46 cm
  • 56.46 cm
  • 66.46 cm
  • 64.46 cm
  • 61.46 cm
Question 7
7.
In the given figure △ABC is an equilateral triangle whose area is 173.21 sq.cm. With each vertex of the triangle as center, a circle is drawn with radius equal to half the length of the side of the triangle . Find the area of the shaded region
  • 19.06 sq.cm
  • 21.06 sq.cm
  • 16.06 sq.cm
  • 11.06 sq.cm
  • 13.06 sq.cm
Question 8
8.
In a right angled triangle △PQR, if the area is 160 sq.cm and corresponding height of side QR = 16 cm, then side RP =
  • 25.61 cm
  • 22.61 cm
  • 30.61 cm
  • 28.61 cm
  • 20.61 cm
Question 9
9.
In the given figure ,PQRS is the diameter of the circle of radius 15.00 cm and PQ = QR = RS. Find the perimeter of the shaded region
  • 99.29 cm
  • 91.29 cm
  • 97.29 cm
  • 94.29 cm
  • 89.29 cm
Question 10
10.
In an isosceles right angled triangle △PQR, if area = 128 sq.cm, then side PQ =
  • 19.00 cm
  • 13.00 cm
  • 21.00 cm
  • 16.00 cm
  • 11.00 cm