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ICSE Grade IX - Mid-Point and Intercept Theorems
Question
1
1.
In the given figure, points P , Q and R are the mid-points of sides NO, OM and MN of △MNO. Which of the following are true?
a)
Area of △MNO = 4 times area of △PQR
b)
Area of trapezium NOQR is thrice the area of △MRQ
c)
Area of trapezium
NOQR
is
1
4
the area of
△MNO
d)
All four small triangles have equal areas
e)
Area of
△MNO
=
1
3
area of
△PQR
{e,b}
{c,a}
{a,b,d}
{c,e,d}
{c,a,b}
Question
2
2.
In the given figure
△BCD
,
E
is the mid-point of
BC
and
EF
∥
CD
,
then
FD
=
BE
BC
DB
EC
BF
Question
3
3.
In the given figure, IJKL is a parallelogram such that Q is the mid-point of IJ and IJ = 2LI. Find ∠LQK
91°
90°
92°
88°
89°
Question
4
4.
In the given figure, if A, Q, R, S, T, U are equidistant and RP ∥ UB and AB = 20 cm and AP = 8 cm. Find PB
12.00 cm
14.00 cm
13.00 cm
11.00 cm
10.00 cm
Question
5
5.
BCDE is a quadrilateral. R, S, T and U are mid-points of BC, CD, DE and EB respectively.If BD = 28 cm and CE = 17 cm, find the measure of the sides of RSTU.
14 cm
,
7 cm
,
14 cm
,
7 cm
15 cm
,
8.5 cm
,
15 cm
,
8.5 cm
14 cm
,
8.5 cm
,
14 cm
,
8.5 cm
14 cm
,
5 cm
,
14 cm
,
5 cm
16 cm
,
8.5 cm
,
16 cm
,
8.5 cm
Question
6
6.
In the given figure, △BCD is a triangle.
E
,
F
&
G
are mid-points of
CD
,
DB
&
BC
respectively.
Given
EF = 9 cm
,
FG = 9 cm
&
GE = 9 cm
,
find the sides of the triangle.
19 cm
,
18 cm
&
18 cm
18 cm
,
18 cm
&
18 cm
18 cm
,
18 cm
&
21 cm
18 cm
,
17 cm
&
18 cm
16 cm
,
18 cm
&
18 cm
Question
7
7.
In the given figure
△FGH
,
I
is the mid-point of
FG
and
IJ
∥
GH
,
then
IG
=
FG
FI
FJ
HF
JH
Question
8
8.
In the given figure, DEFG is a parallelogram
such that
H
and
I
are mid-points of sides
DE
&
FG
.
DI
meets
EG
at
T
and
FH
meets
EG
at
U
. Given
EG
=
17 cm
, find
TU
3.67 cm
7.67 cm
5.67 cm
6.67 cm
4.67 cm
Question
9
9.
In the given figure
△JKL
,
M
is the mid-point of
JK
and
MN
∥
KL
,
then
JN
=
LJ
2
KL
2
JK
2
KL
JM
Question
10
10.
In the given figure, three lines l , m and n are such that l ∥ m ∥ n.
Two transversals PQ and RS intersect them at the points A , B , C and D , E , F respectively.
∠FDA =
∠DAF
∠ACF
∠ABH
∠FEH
∠EHF
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