ICSE Board Practice

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ICSE Grade IX - Mid-Point and Intercept Theorems

Question 1

1.	In the given figure, △BCD is a triangle. E , F & G are mid-points of CD , DB & BC respectively. Given EF = 9 cm , FG = 9 cm & GE = 9 cm , find the sides of the triangle.
	18 cm , 18 cm & 20 cm 16 cm , 18 cm & 18 cm 19 cm , 18 cm & 18 cm 18 cm , 18 cm & 18 cm 18 cm , 17 cm & 18 cm

Question 2

2.	In the given figure, three lines l , m and n are such that l ∥ m ∥ n. Two transversals PQ and RS intersect them at the points A , B , C and D , E , F respectively. △ACF ∼
	△DCF △FDA △FEH △DAE △ABH

Question 3

3.	In the given figure △ABC , D is the mid-point of     AB     and     DE     ∥   BC     , then   DB =
	AB AD AE EC CA

Question 4

4.	In the given figure, the area of the △EFG is x sq.cm. H,I,J are the mid-points of the sides FG , GE and EF respectively. The area of the △HIJ is
	1 3 of area of △EFG 1 4 of area of △EFG 1 2 of area of △EFG 3 4 of area of △EFG 2 3 of area of △EFG

Question 5

5.	In the given figure, points D , E and F are the mid-points of sides BC, CA and AB of △ABC. Which of the following are true?
	a) Area of trapezium BCEF is 1 4 the area of △ABC b) Area of △ABC = 1 3 area of △DEF c) Area of △ABC = 4 times area of △DEF d) Area of trapezium BCEF is thrice the area of △AFE e) All four small triangles have equal areas
	{a,b,e} {a,c} {b,d} {a,c,d} {c,d,e}

Question 6

6.	From the given figure and values, find x
	( 0 , 7 ) ( 9 , 2 ) ( 0 , 6 ) ( 3 , 7 ) ( 1 , 8 )

Question 7

7.	In the given figure, IJKL is a parallelogram such that M and N are mid-points of sides IJ & KL . IN meets JL at T and KM meets JL at U . Given JL = 15 cm , find JU
	3.00 cm 4.00 cm 6.00 cm 5.00 cm 7.00 cm

Question 8

8.	In the given figure △BCD , E is the mid-point of     BC     and     EF     ∥   CD     , then   BF =
	BC BE DB EC FD

Question 9

9.	In the given figure △ABC , D is the mid-point of     AB     and     DE     ∥   BC     , then   AD =
	BC 2 AE AB 2 CA 2 BC

Question 10

10.	In the given figure △FGH , I is the mid-point of     FG     and     IJ     ∥   GH     , then   FJ =
	FI FG 2 GH 2 HF 2 GH

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