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ICSE Grade IX - Pythagoras Theorem
Question
1
1.
In a right angled triangle, if one of the angles is 49.76°, find the third angle
55.24°
50.24°
40.24°
45.24°
70.24°
Question
2
2.
In the given figure, △BCD is a triangle with BE being the median of CD. Then
BC
2
+
BD
2
=
2
CE
2
+
2
BE
2
BC
2
+
BD
2
=
2
ED
2
+
2
BE
2
BC
2
+
BD
2
=
2
CE
2
+
2
ED
2
BC
2
+
BD
2
=
CD
2
BC
2
+
BD
2
=
BE
2
Question
3
3.
In a right angled triangle △PQR, if the base QR = 19 cm and the corresponding height is 10 cm, then corresponding height of side RP =
10.85 cm
7.85 cm
8.85 cm
9.85 cm
6.85 cm
Question
4
4.
In a right angled triangle △PQR, if QR = 11 cm, PQ = 19 cm are the lengths of perpendicular sides , then area of the triangle =
78.50 sq.cm
104.50 sq.cm
126.50 sq.cm
111.50 sq.cm
102.50 sq.cm
Question
5
5.
In a right angled triangle △PQR, if QR = 14 cm is one of the perpendicular sides and RP = 18.44 cm is the hypotenuse, then perimeter of the triangle =
47.44 cm
44.44 cm
49.44 cm
41.44 cm
39.44 cm
Question
6
6.
In an isosceles right angled triangle △PQR, if corresponding height to the base QR is 19 cm, then corresponding height of side RP =
10.44 cm
8.44 cm
16.44 cm
13.44 cm
18.44 cm
Question
7
7.
In a right angled triangle △PQR, if the base QR = 10 cm and the corresponding height is 13 cm, then perimeter of the triangle =
44.40 cm
36.40 cm
39.40 cm
42.40 cm
34.40 cm
Question
8
8.
In an isosceles right angled triangle △PQR, if RP = 26.87 cm is the hypotenuse, then corresponding height of side RP =
18.44 cm
8.44 cm
13.44 cm
16.44 cm
10.44 cm
Question
9
9.
In an isosceles right angled triangle △PQR, if corresponding height to the base QR is 16 cm, then side RP =
17.63 cm
22.63 cm
27.63 cm
25.63 cm
19.63 cm
Question
10
10.
In a right angled triangle △PQR, if the area is 80 sq.cm and base QR = 10 cm, then side RP =
18.87 cm
21.87 cm
15.87 cm
13.87 cm
23.87 cm
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