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ICSE Grade IX - Pythagoras Theorem
Question
1
1.
In a right angled triangle △PQR, if the base QR = 20 cm and the corresponding height is 14 cm, then side PQ =
14.00 cm
19.00 cm
9.00 cm
11.00 cm
17.00 cm
Question
2
2.
In a right angled triangle △PQR, if QR = 14 cm, PQ = 20 cm are the lengths of perpendicular sides , then area of the triangle =
128.00 sq.cm
124.00 sq.cm
140.00 sq.cm
164.00 sq.cm
143.00 sq.cm
Question
3
3.
In a right angled triangle △PQR, if QR = 16 cm, PQ = 11 cm are the lengths of perpendicular sides , then side RP =
22.42 cm
14.42 cm
19.42 cm
16.42 cm
24.42 cm
Question
4
4.
In a right angled triangle △PQR, if QR = 15 cm is one of the perpendicular sides and RP = 19.85 cm is the hypotenuse, then corresponding height of side PQ =
15.00 cm
18.00 cm
10.00 cm
12.00 cm
20.00 cm
Question
5
5.
In the given figure, CDEF is a rhombus. Which of the following are true?
a)
2
CD
2
=
CE
2
+
DF
2
b)
4
CD
2
=
CE
2
+
DF
2
c)
CD
2
+
DE
2
+
EF
2
+
CF
2
=
CE
2
+
DF
2
d)
DE
2
+
EF
2
=
DF
2
e)
CD
2
+
DE
2
=
CE
2
{d,c,b}
{b,c}
{e,a,b}
{d,c}
{a,b}
Question
6
6.
In a right angled triangle, if the two non-hypotenuse sides are 18 cm and 80 cm, find the hypotenuse
83.00 cm
84.00 cm
81.00 cm
82.00 cm
80.00 cm
Question
7
7.
In a right angled triangle △PQR, if the base QR = 11 cm and the corresponding height is 20 cm, then corresponding height of side RP =
7.64 cm
10.64 cm
9.64 cm
11.64 cm
8.64 cm
Question
8
8.
In a right angled triangle △PQR, if the area is 112 sq.cm and corresponding height of side QR = 16 cm, then corresponding height of side PQ =
14.00 cm
9.00 cm
11.00 cm
17.00 cm
19.00 cm
Question
9
9.
In the given figure, △EFG is isosceles with EF = EG and FH ⟂ EG. Then
FH
2
+
GH
2
= 2
GH
.
EH
FH
2
+
EH
2
= 2
GH
.
EH
FH
2
−
EH
2
= 2
GH
.
EH
FH
2
−
GH
2
= 2
GH
.
EH
Question
10
10.
In an equilateral triangle ABC, the side BC is trisected at D. Then
3 AD
2
=
7 AB
2
7 AD
2
=
3 AB
2
9 AD
2
=
7 AB
2
7 AD
2
=
9 AB
2
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