SSC Board Practice

Class VI Class VII Class VIII Class IX Class X
SSC Grade VII - Area and Perimeter
Question 1
1.
If the inner rectangle area, outer rectangle area and width of a rectangular path are 90.00 sq.cm, 127.44 sq.cm and 0.90 cm respectively, the outer breadth of the rectangular path =
  • 7.80 cm
  • 10.80 cm
  • 5.80 cm
  • 13.80 cm
  • 15.80 cm
Question 2
2.
If the side of an equilateral triangle is 12 cm, the height of the equilateral triangle =
  • 13.39 cm
  • 15.39 cm
  • 7.39 cm
  • 10.39 cm
  • 5.39 cm
Question 3
3.
In an isosceles right angled triangle △PQR, if corresponding height to the base QR is 18 cm, then side PQ =
  • 21.00 cm
  • 18.00 cm
  • 15.00 cm
  • 23.00 cm
  • 13.00 cm
Question 4
4.
Find the area of the shaded region in the adjoining figure, given that EFGH is a square of side 15 cm, GI = 9 cm, JE = 10 cm and FK = 5 cm
  • 122.50 sq.cm
  • 120.50 sq.cm
  • 121.50 sq.cm
  • 123.50 sq.cm
  • 124.50 sq.cm
Question 5
5.
Find the area of the shaded region
  • 517.00 sq.cm
  • 515.00 sq.cm
  • 519.00 sq.cm
  • 516.00 sq.cm
  • 518.00 sq.cm
Question 6
6.
In the given figure, find the area of the shaded region
  • 183.00 sq.cm
  • 205.00 sq.cm
  • 214.00 sq.cm
  • 198.00 sq.cm
  • 196.00 sq.cm
Question 7
7.
If the inner length, outer breadth and width of a rectangular path are 9.00 cm, 7.00 cm and 1.00 cm respectively, the area of the outer rectangle of the rectangular path =
  • 74.00 sq.cm
  • 82.00 sq.cm
  • 77.00 sq.cm
  • 80.00 sq.cm
  • 72.00 sq.cm
Question 8
8.
If the inner length, outer breadth and area of the inner rectangle of a rectangular path are 10.00 cm, 11.20 cm and 80.00 sq.cm respectively, the area of the rectangular path =
  • 62.84 sq.cm
  • 67.84 sq.cm
  • 72.84 sq.cm
  • 70.84 sq.cm
  • 64.84 sq.cm
Question 9
9.
In an isosceles right angled triangle △PQR, if corresponding height to the base QR is 16 cm, then area of the triangle =
  • 101.00 sq.cm
  • 120.00 sq.cm
  • 152.00 sq.cm
  • 144.00 sq.cm
  • 128.00 sq.cm
Question 10
10.
In an isosceles triangle △ABC, if base BC = 14 cm and area is 49.99 sq.cm, then corresponding height of side BC =
  • 5.14 cm
  • 7.14 cm
  • 9.14 cm
  • 6.14 cm
  • 8.14 cm