CBSE Board Practice

Class VI Class VII Class VIII Class IX Class X
CBSE Grade VII - Perimeter and Area
Question 1
1.
If perimeter of an equilateral triangle 36 cm, the area of the equilateral triangle =
  • 62.35 sq.cm
  • 67.35 sq.cm
  • 59.35 sq.cm
  • 65.35 sq.cm
  • 57.35 sq.cm
Question 2
2.
In a right angled triangle △PQR, if the base QR = 17 cm and the corresponding height is 20 cm, then area of the triangle =
  • 183.00 sq.cm
  • 168.00 sq.cm
  • 155.00 sq.cm
  • 170.00 sq.cm
  • 177.00 sq.cm
Question 3
3.
If the outer side of a square path is 10.00 cm and area of the square path is 19.00 sq.cm, the area of the outer square =
  • 112.00 sq.cm
  • 87.00 sq.cm
  • 100.00 sq.cm
  • 84.00 sq.cm
  • 108.00 sq.cm
Question 4
4.
If the outer length, outer breadth and width of a rectangular path are 10.60 cm, 9.60 cm and 0.80 cm respectively, the area of the inner rectangle of the rectangular path =
  • 75.00 sq.cm
  • 67.00 sq.cm
  • 72.00 sq.cm
  • 77.00 sq.cm
  • 69.00 sq.cm
Question 5
5.
If area of the circle is 78.57 sq.cm, the radius of the circle is
  • 6.00 cm
  • 7.00 cm
  • 5.00 cm
  • 3.00 cm
  • 4.00 cm
Question 6
6.
In parallelogram PQRS, if base PQ = 19.00 cm and area is 154.09 sq.cm, the corresponding height to the base PQ is
  • 8.11 cm
  • 9.11 cm
  • 10.11 cm
  • 6.11 cm
  • 7.11 cm
Question 7
7.
If the outer length, inner breadth and area of the outer rectangle of a rectangular path are 11.00 cm, 5.00 cm and 66.00 sq.cm respectively, the area of the rectangular path =
  • 13.00 sq.cm
  • 19.00 sq.cm
  • 16.00 sq.cm
  • 11.00 sq.cm
  • 21.00 sq.cm
Question 8
8.
If the outer length, inner breadth and area of the inner rectangle of a rectangular path are 12.40 cm, 6.00 cm and 60.00 sq.cm respectively, the area of the outer rectangle of the rectangular path =
  • 104.16 sq.cm
  • 82.16 sq.cm
  • 98.16 sq.cm
  • 111.16 sq.cm
  • 131.16 sq.cm
Question 9
9.
Find the area of the shaded region given below
  • 874.00 sq.m
  • 880.00 sq.m
  • 857.00 sq.m
  • 841.00 sq.m
Question 10
10.
In an isosceles triangle △ABC, if BC = 16 cm, AB = CA = 20 cm, then perimeter of the triangle =
  • 61.00 cm
  • 59.00 cm
  • 53.00 cm
  • 56.00 cm
  • 51.00 cm