SSC Board Practice

Class VI Class VII Class VIII Class IX Class X
SSC Grade IX - Circles
Question 1
1.
Which of the following statements are true?
a)
Angle subtended by the major arc in its alternate segment is obtuse.
b)
Angle subtended by the major arc at the centre is acute.
c)
Angle subtended in the major segment is obtuse.
d)
If two chords are equal, then they are equidistant from the centre of the circle.
e)
The angle subtended in a semicircle is a right angle.
  • {b,c,e}
  • {b,a,d}
  • {b,a}
  • {c,d}
  • {a,d,e}
Question 2
2.
O is the centre of the circle and OI = HI. Find ∠IOG
  • 125°
  • 130°
  • 150°
  • 120°
  • 135°
Question 3
3.
In the given figure, O is the centre of the circle , chord IL is equal to chord LK. If ∠IOJ = 80° and ∠ILK = 111°, find ∠JKL
  • 74.5°
  • 79.5°
  • 104.5°
  • 89.5°
  • 84.5°
Question 4
4.
In the given figure, O is the centre of the circle. If ∠JHI = 65.49° and ∠HIJ = 76.39°, find the angle ∠HKI
  • 43.12°
  • 68.12°
  • 38.12°
  • 53.12°
  • 48.12°
Question 5
5.
If an arc subtends an angle of  x° in its alternate segment, then the angle is subtends at the centre is
  • x°
  • x°
    2
  • 2x°
  • 4x°
Question 6
6.
Which of the following statements are true?
a)
A cyclic quadrilateral is a regular polygon.
b)
If a rhombus is cyclic, it is a square.
c)
If a kite is cyclic, it is a square.
d)
If a trapezium is cyclic, it is a rectangle.
e)
If a parallelogram is cyclic, it is a rectangle.
  • {b,e}
  • {a,b}
  • {c,e}
  • {c,e,b}
  • {d,a,b}
Question 7
7.
In the given figure, △HIJ is an isosceles such that HI = HJ. Given HO = 10 cm, HI = HJ = 16 cm, find IJ
  • 21.20 cm
  • 19.20 cm
  • 20.20 cm
  • 18.20 cm
  • 17.20 cm
Question 8
8.
In the given figure, O is the centre of the circle. If ∠FGJ = 107° and ∠GHI = 109°, find ∠HKI
  • 36°
  • 51°
  • 41°
  • 46°
  • 66°
Question 9
9.
In the given figure, a pentagon is inscribed in a circle with centre O. Given GH = HI = IJ and ∠GHI = 118°. Find ∠GFJ
  • 108°
  • 123°
  • 103°
  • 98°
  • 93°
Question 10
10.
In the given figure, DEFG is a cyclic quadrilateral. If ∠DFE = 32° and ∠FGE = 47°, find ∠DGF
  • 79°
  • 94°
  • 89°
  • 84°
  • 109°