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SSC Board Practice
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Class VI
Class VII
Class VIII
Class IX
Class X
SSC Grade X - Similar Triangles
Question
1
1.
In the given figure, ∠ECD = 42.77°, find the value of y =
47.23°
49.23°
45.23°
46.23°
48.23°
Question
2
2.
In the given figure,
△CED
is right-angled at
E
.
Q
is the mid-point of
CE
and
R
is the mid-point of
DE
.
Which of the following cases are true?
a)
4
DQ
2
=
4
DE
2
+
CE
2
b)
4
CR
2
=
4
DE
2
+
CE
2
c)
4
CR
2
=
4
CE
2
+
DE
2
d)
4
DQ
2
=
4
CE
2
+
DE
2
e)
4 (
CR
2
+
DQ
2
) =
5
CD
2
{b,a}
{d,c}
{b,a,c}
{b,d,e}
{a,c,e}
Question
3
3.
In the given figure, in △CDE, 'O' is a point inside the triangle. OF ⟂ DE, OG ⟂ CE and OH ⟂ CD. Then
CH
2
+
DF
2
+
EG
2
=
CG
2
+
EF
2
+
DH
2
CH
2
+
DF
2
+
EG
2
=
OF
2
+
OG
2
+
OH
2
CH
2
+
DF
2
+
EG
2
=
OH
.
OF
+
OF
.
OG
+
OG
.
OH
CH
2
+
DF
2
+
EG
2
=
OC
.
OD
+
OD
.
OE
+
OE
.
OC
Question
4
4.
In the given figure, △ABC and △STU are such that
AB
ST
=
BC
TU
=
CA
US
.
Identify the property by which the two triangles are similar
not similar
SSS Similarity
AAA Similarity
SAS Similarity
Question
5
5.
In the given figure, in △CDE, 'O' is a point inside the triangle. OF ⟂ DE, OG ⟂ CE and OH ⟂ CD. Then
CH
2
+
DF
2
+
EG
2
=
OH
2
+
OG
2
+
OF
2
CH
2
+
DF
2
+
EG
2
=
OC
2
+
OD
2
+
OE
2
−
OF
2
−
OG
2
−
OH
2
CH
2
+
DF
2
+
EG
2
=
CD
2
+
FE
2
+
EC
2
−
DH
2
−
EF
2
−
GC
2
CH
2
+
DF
2
+
EG
2
=
OC
2
+
OD
2
+
OE
2
+
OF
2
+
OG
2
+
OH
2
Question
6
6.
JKLM is a cyclic trapezium. Diagonals KM and JL intersect at N. If MJ = 17 cm, find KL
18 cm
15 cm
19 cm
17 cm
16 cm
Question
7
7.
In the given figure, O is a point in the interior of the rectangle CDEF. Then
OC
2
+
OD
2
+
OE
2
+
OF
2
=
CE
2
+
DF
2
OC
2
−
OE
2
=
OD
2
−
OF
2
OC
2
+
OE
2
=
OD
2
+
OF
2
OC
2
+
OD
2
+
OE
2
+
OF
2
=
CD
2
+
DE
2
+
EF
2
+
FC
2
Question
8
8.
In the given figure, △IJK, IL ⟂ JK. Which of the following are true?
a)
IJ
2
+
JL
2
=
IK
2
+
KL
2
b)
IJ
2
+
IK
2
=
JL
2
+
KL
2
c)
IJ
2
−
IK
2
=
JL
2
−
KL
2
d)
IL
2
=
2
JL
.
KL
e)
IJ
2
−
JL
2
=
IK
2
−
KL
2
{b,e}
{a,c}
{d,a,c}
{b,e,c}
{c,e}
Question
9
9.
In the given figure, △IJK is a triangle in which IL is the internal bisector of ∠I and KM ∥ LI meeting JI produced at M . ∠KIL =
∠JLI
∠LKI
∠MIK
∠ILK
∠LIJ
Question
10
10.
In the given figure,
FG
∥
DE
.
If
CF
FD
=
5
4
and
CE
=
13.9 cm
, find
CG
6.72 cm
8.72 cm
9.72 cm
7.72 cm
5.72 cm
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