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SSC Board Practice
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Class VI
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Class X
SSC Grade X - Similar Triangles
Question
1
1.
The ratio of the bases of two triangles ABC and DEF is
4
:
6
.
If the triangles are equal in area, then the ratio of their heights is
3
:
6
6
:
4
5
:
6
4
:
8
4
:
3
Question
2
2.
In the given figure, △ABC, TU ∥ BC such that
area of
△ATU
= area of
TUCB
. Find
AT
AB
1
2
4
√
2
1
1
2
√
2
1
2
√
5
1
2
√
-1
Question
3
3.
In the given figure, ∠DAB = ∠CAD and AD ∥ EC and AB = 15 cm, BD = 7 cm and DC = 9 cm. Find AE
21.29 cm
17.29 cm
20.29 cm
18.29 cm
19.29 cm
Question
4
4.
In the given figure,
△DFE
is right-angled at
F
.
S
is the mid-point of
DF
and
T
is the mid-point of
EF
.
Which of the following cases are true?
a)
4
ES
2
=
4
EF
2
+
DF
2
b)
4
DT
2
=
4
EF
2
+
DF
2
c)
4
DT
2
=
4
DF
2
+
EF
2
d)
4 (
DT
2
+
ES
2
) =
5
DE
2
e)
4
ES
2
=
4
DF
2
+
EF
2
{a,c,d}
{e,c}
{b,a,c}
{b,a}
{b,e,d}
Question
5
5.
If the measures are as shown in the given figure, find CD
22.0 cm
19.0 cm
20.0 cm
23.0 cm
21.0 cm
Question
6
6.
In the given figure, ST ∥ GH and FS = 12.6 cm, ST = 15 cm and GH = 25 cm, find FG
21.0 cm
23.0 cm
22.0 cm
19.0 cm
20.0 cm
Question
7
7.
In the given figure, E is a point on side CD of △BCD such that ∠DBC = ∠BED = 108° , ∠EDB = 25°. Find ∠DBE
45°
49°
46°
47°
48°
Question
8
8.
In the given figure, △BCD is an acute angled triangle and BE ⟂ CD. Then
BD
2
=
BC
2
+
CD
2
+
2
CD
.
CE
BD
2
=
BC
2
+
CD
2
−
BE
2
BD
2
=
BC
2
+
CD
2
−
2
BC
.
CD
BD
2
=
BC
2
+
CD
2
+
2
BC
.
CD
BD
2
=
BC
2
+
CD
2
−
2
CD
.
CE
Question
9
9.
From the given figure and values, find x
(
34
,
33
)
(
34
,
34
)
(
37
,
34
)
(
36
,
36
)
(
35
,
35
)
Question
10
10.
In the given figure, GHI is a triangle and 'O' is a point inside △GHI. The angular bisector of ∠HOG, ∠IOH & ∠GOI meet GH, HI & IG at J, K & L respectively . Then
GJ . HK . IL = JH . KI . LG
GJ . HK . IL = OJ . OK . OL
GJ . HK . IL = OG . OH . OI
GJ . HK . IL = GH . HI . IG
GJ . HK . IL = JK . KL . LJ
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