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Class VI
Class VII
Class VIII
Class IX
Class X
CBSE Grade IX - Linear Equations in two Variables
Question
1
1.
Any line parallel to x-axis is
a vertical line
an oblique line
a horizontal line
a curved line
Question
2
2.
Which of the following equations satisfy the given points
(
3
,
(
−
2
)
)
,
(
3
,
(
−
1
)
)
,
(
3
,
0
)
,
(
3
,
1
)
,
(
3
,
2
)
?
y
=
(
−
2
3
x
−
6
)
(
−
4
x
−
6
y
+
2
)
=
0
x
=
3
x
=
(
2
3
y
+
25
3
)
(
8
x
+
2
y
−
1
)
=
0
Question
3
3.
Which of the following equations satisfy the given points
(
(
−
2
)
,
3
)
,
(
(
−
1
)
,
3
)
,
(
0
,
3
)
,
(
1
,
3
)
,
(
2
,
3
)
?
y
=
3
(
5
x
+
6
y
−
3
)
=
0
(
−
11
x
−
9
y
−
34
)
=
0
x
=
8
y
=
(
−
11
9
x
+
115
9
)
Question
4
4.
Equation of a straight line which is parallel to x-axis (where k is a constant) is
x
=
0
x
=
k
y
=
k
y
=
0
x
=
y
Question
5
5.
Which of the displayed lines represent the equation
y
=
(
5
3
x
+
1
)
line with point
R
line with point
S
line with point
P
line with point
T
line with point
Q
Question
6
6.
Any line parallel to y-axis is
a curved line
a horizontal line
a vertical line
an oblique line
Question
7
7.
The value of
y
in terms of other variables and constant in
(
−
8
x
+
6
y
−
6
)
=
(
6
x
+
9
y
+
3
)
is
y
=
(
−
14
3
x
)
y
=
(
−
22
5
x
−
3
)
y
=
(
−
6
x
−
3
)
y
=
(
−
14
3
x
−
5
)
y
=
(
−
14
3
x
−
3
)
Question
8
8.
Find the set of points satisfying the equation
x
=
(
1
3
y
+
26
3
)
(
(
−
2
)
,
(
−
32
)
)
,
(
(
−
1
)
,
(
−
29
)
)
,
(
0
,
(
−
26
)
)
,
(
0
,
(
−
22
)
)
,
(
2
,
(
−
20
)
)
(
(
−
2
)
,
(
−
32
)
)
,
(
(
−
1
)
,
(
−
29
)
)
,
(
(
−
2
)
,
(
−
28
)
)
,
(
1
,
(
−
23
)
)
,
(
2
,
(
−
20
)
)
(
(
−
2
)
,
(
−
32
)
)
,
(
(
−
1
)
,
(
−
29
)
)
,
(
0
,
(
−
26
)
)
,
(
1
,
(
−
23
)
)
,
(
2
,
(
−
20
)
)
(
(
−
2
)
,
(
−
32
)
)
,
(
(
−
1
)
,
(
−
29
)
)
,
(
1
,
(
−
27
)
)
,
(
1
,
(
−
23
)
)
,
(
2
,
(
−
20
)
)
(
(
−
2
)
,
(
−
32
)
)
,
(
(
−
1
)
,
(
−
29
)
)
,
(
0
,
(
−
26
)
)
,
(
1
,
(
−
23
)
)
,
(
4
,
(
−
18
)
)
Question
9
9.
The equation of y-axis is
y
=
x
x
=
1
y
=
1
x
=
0
y
=
0
Question
10
10.
The value of
x
in terms of other variables and constant in
(
9
x
+
y
−
1
)
=
(
5
x
+
2
y
−
5
)
is
x
=
(
1
4
y
−
1
)
x
=
(
1
4
y
+
1
)
x
=
(
1
2
y
−
1
)
x
=
(
1
4
y
−
4
)
x
=
(
1
6
y
−
1
)
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