CBSE Board Practice

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CBSE Grade IX - Areas of Parallelograms and Triangles
Question 1
1.
In parallelogram PQRS, if base PQ = 17.00 cm and the corresponding height is 13.77 cm, then area of the parallelogram =
  • 230.09 sq.cm
  • 234.09 sq.cm
  • 206.09 sq.cm
  • 258.09 sq.cm
  • 237.09 sq.cm
Question 2
2.
In a right angled triangle △PQR, if QR = 13 cm, PQ = 16 cm are the lengths of perpendicular sides , then area of the triangle =
  • 96.00 sq.cm
  • 107.00 sq.cm
  • 79.00 sq.cm
  • 116.00 sq.cm
  • 104.00 sq.cm
Question 3
3.
In a right angled triangle △PQR, if the base QR = 13 cm and the corresponding height is 12 cm, then area of the triangle =
  • 75.00 sq.cm
  • 81.00 sq.cm
  • 83.00 sq.cm
  • 73.00 sq.cm
  • 78.00 sq.cm
Question 4
4.
In △PQR, if QR = 17 cm, RP = 10 cm and the corresponding height of side QR = 9.56 cm, then area of the triangle =
  • 76.24 sq.cm
  • 78.24 sq.cm
  • 81.24 sq.cm
  • 86.24 sq.cm
  • 84.24 sq.cm
Question 5
5.
In △PQR, if base QR = 12 cm and the corresponding height of side QR = 15.32 cm, then area of the triangle =
  • 86.90 sq.cm
  • 96.90 sq.cm
  • 91.90 sq.cm
  • 88.90 sq.cm
  • 94.90 sq.cm
Question 6
6.
In an isosceles right angled triangle △PQR, if corresponding height to the base QR is 15 cm, then area of the triangle =
  • 112.50 sq.cm
  • 99.50 sq.cm
  • 129.50 sq.cm
  • 114.50 sq.cm
  • 108.50 sq.cm
Question 7
7.
In an isosceles right angled triangle △PQR, if QR = 11 cm is one of the equal sides, then area of the triangle =
  • 55.50 sq.cm
  • 60.50 sq.cm
  • 63.50 sq.cm
  • 57.50 sq.cm
  • 65.50 sq.cm
Question 8
8.
In an isosceles triangle △ABC, if base BC = 19 cm and the corresponding height is 12.87 cm, then area of the triangle =
  • 115.31 sq.cm
  • 146.31 sq.cm
  • 124.31 sq.cm
  • 104.31 sq.cm
  • 122.31 sq.cm
Question 9
9.
In a right angled triangle △PQR, if QR = 12 cm is one of the perpendicular sides and RP = 23.32 cm is the hypotenuse, then area of the triangle =
  • 106.00 sq.cm
  • 135.00 sq.cm
  • 142.00 sq.cm
  • 120.00 sq.cm
Question 10
10.
In trapezium ABCD, if distance between the parallel sides is 8.25 cm and lengths of the parallel sides AB = 16.00 cm and CD = 6.00 cm, then area of the trapezium =
  • 93.75 sq.cm
  • 95.75 sq.cm
  • 85.75 sq.cm
  • 87.75 sq.cm
  • 90.75 sq.cm