CBSE Board Practice

CBSE Grade IX - Heron's Formula
Question 1
1.
In an isosceles triangle △ABC, if base BC = 12 cm and area is 48 sq.cm, then corresponding height of side BC =
  • 6.00 cm
  • 8.00 cm
  • 7.00 cm
  • 9.00 cm
  • 10.00 cm
Question 2
2.
In an isosceles triangle △ABC, if BC = 18 cm, AB = CA = 11 cm, then corresponding height of side AB =
  • 10.35 cm
  • 5.35 cm
  • 13.35 cm
  • 15.35 cm
  • 7.35 cm
Question 3
3.
In an isosceles triangle △ABC, the corresponding height of the side BC is 9.22 cm and area is 55.32 sq.cm, then side CA =
  • 14.00 cm
  • 8.00 cm
  • 11.00 cm
  • 6.00 cm
  • 16.00 cm
Question 4
4.
A traffic sign board is in the shape of an equilateral triangle . If its perimeter is 36 cm, what is its area ?
  • 59.35 sq.cm
  • 67.35 sq.cm
  • 57.35 sq.cm
  • 62.35 sq.cm
  • 65.35 sq.cm
Question 5
5.
In △PQR, if QR = 14 cm, RP = 15 cm, PQ = 13 cm, then corresponding height of side QR =
  • 9.00 cm
  • 15.00 cm
  • 7.00 cm
  • 17.00 cm
  • 12.00 cm
Question 6
6.
Reshma has a triangular field with sides 160 m, 90 m and 200 m. She wanted to grow carrots and cabbages. She divided the field into two parts by joining the mid-point of the longest side to the opposite vertex, and grew carrots in one part and cabbages in the other part. How much area has been used for carrots.
  • 3472.81 sq.m
  • 3512.81 sq.m
  • 3732.81 sq.m
  • 3582.81 sq.m
  • 3392.81 sq.m
Question 7
7.
In an isosceles triangle △ABC, the corresponding height of the side BC is 12 cm and area is 60 sq.cm, then corresponding height of side AB =
  • 10.23 cm
  • 7.23 cm
  • 11.23 cm
  • 8.23 cm
  • 9.23 cm
Question 8
8.
In an isosceles triangle △ABC, if BC = 18 cm, AB = CA = 10 cm, then corresponding height of side CA =
  • 9.85 cm
  • 8.85 cm
  • 6.85 cm
  • 5.85 cm
  • 7.85 cm
Question 9
9.
In an isosceles triangle △ABC, if base BC = 18 cm and area is 71.44 sq.cm, then side CA =
  • 17.00 cm
  • 9.00 cm
  • 15.00 cm
  • 12.00 cm
  • 7.00 cm
Question 10
10.
In △PQR, if QR = 19 cm, RP = 14 cm and the corresponding height of side QR = 8.82 cm, then perimeter of the triangle =
  • 40.00 cm
  • 48.00 cm
  • 45.00 cm
  • 50.00 cm
  • 42.00 cm