CBSE Board Practice

Class VI Class VII Class VIII Class IX Class X
CBSE Grade IX - Heron's Formula
Question 1
1.
In an isosceles triangle △ABC, if BC = 16 cm, AB = CA = 11 cm, then area of the triangle =
  • 57.40 sq.cm
  • 55.40 sq.cm
  • 60.40 sq.cm
  • 65.40 sq.cm
  • 63.40 sq.cm
Question 2
2.
In an isosceles triangle △ABC, if BC = 16 cm, CA = AB and perimeter is 52 cm, then corresponding height of side CA =
  • 17.33 cm
  • 14.33 cm
  • 19.33 cm
  • 11.33 cm
  • 9.33 cm
Question 3
3.
A field is in the shape of a trapezium whose parallel sides are 48 m and 18 m. The non parallel sides are 22 m and 30 m. Find the area of the field.
  • 670.44 sq.m
  • 683.44 sq.m
  • 688.44 sq.m
  • 675.44 sq.m
  • 647.44 sq.m
Question 4
4.
In an isosceles triangle △ABC, if base BC = 10 cm and the corresponding height is 17.29 cm, then corresponding height of side AB =
  • 9.61 cm
  • 10.61 cm
  • 7.61 cm
  • 8.61 cm
  • 11.61 cm
Question 5
5.
A traffic sign board is in the shape of an equilateral triangle . If its perimeter is 42 cm, what is its area ?
  • 84.87 sq.cm
  • 81.87 sq.cm
  • 87.87 sq.cm
  • 89.87 sq.cm
  • 79.87 sq.cm
Question 6
6.
In an isosceles triangle △ABC, the corresponding height of the side BC is 13.75 cm and area is 137.48 sq.cm, then corresponding height of side AB =
  • 21.17 cm
  • 13.17 cm
  • 11.17 cm
  • 19.17 cm
  • 16.17 cm
Question 7
7.
In △PQR, if QR = 12 cm, RP = 12 cm and the corresponding height of side QR = 9.78 cm, then corresponding height of side PQ =
  • 5.67 cm
  • 10.67 cm
  • 15.67 cm
  • 13.67 cm
  • 7.67 cm
Question 8
8.
A triangle and a parallelogram, both have the same base and the same area. If the sides of the triangle are 13 cm, 20 cm and 27 cm, and the parallelogram stands on the base 20 cm, find the height of the parallelogram
  • 5.18 cm
  • 4.18 cm
  • 7.18 cm
  • 8.18 cm
  • 6.18 cm
Question 9
9.
In an isosceles triangle △ABC, if base BC = 12 cm and area is 55.32 sq.cm, then side AB =
  • 11.00 cm
  • 16.00 cm
  • 14.00 cm
  • 6.00 cm
  • 8.00 cm
Question 10
10.
In △PQR, if QR = 12 cm, RP = 20 cm, PQ = 12 cm, then corresponding height of side PQ =
  • 16.06 cm
  • 6.06 cm
  • 11.06 cm
  • 8.06 cm
  • 14.06 cm