CBSE Board Practice

Class VI Class VII Class VIII Class IX Class X
CBSE Grade IX - Heron's Formula
Question 1
1.
In an isosceles triangle △ABC, if base BC = 15 cm and the corresponding height is 10.62 cm, then area of the triangle =
  • 84.64 sq.cm
  • 82.64 sq.cm
  • 76.64 sq.cm
  • 74.64 sq.cm
  • 79.64 sq.cm
Question 2
2.
In an isosceles triangle △ABC, the corresponding height of the side BC is 11.61 cm and area is 110.28 sq.cm, then side CA =
  • 20.00 cm
  • 12.00 cm
  • 18.00 cm
  • 10.00 cm
  • 15.00 cm
Question 3
3.
In an isosceles triangle △ABC, if base BC = 18 cm and area is 119.06 sq.cm, then corresponding height of side CA =
  • 11.88 cm
  • 17.88 cm
  • 9.88 cm
  • 14.88 cm
  • 19.88 cm
Question 4
4.
A farmer has a piece of land in the shape of a rhombus. He decided to divide the land into two equal parts such that both his son and daughter could work on the land to produce different crops. If the perimeter of the land is 680.00 m and one of the diagonals is 190 m, how much area will each get for their crops?
  • 15892.98 sq.m
  • 15092.98 sq.m
  • 12192.98 sq.m
  • 10792.98 sq.m
  • 13392.98 sq.m
Question 5
5.
In an isosceles triangle △ABC, if BC = 17 cm, CA = AB and perimeter is 37 cm, then corresponding height of side AB =
  • 9.96 cm
  • 7.96 cm
  • 6.96 cm
  • 8.96 cm
  • 10.96 cm
Question 6
6.
In △PQR, if QR = 17 cm, RP = 16 cm, PQ = 17 cm, then area of the triangle =
  • 120.00 sq.cm
  • 135.00 sq.cm
  • 133.00 sq.cm
  • 102.00 sq.cm
  • 104.00 sq.cm
Question 7
7.
In △PQR, if QR = 11 cm, RP = 14 cm, PQ = 12 cm, then corresponding height of side RP =
  • 10.10 cm
  • 9.10 cm
  • 8.10 cm
  • 11.10 cm
  • 7.10 cm
Question 8
8.
In an isosceles triangle △ABC, if base BC = 17 cm and the corresponding height is 6.98 cm, then corresponding height of side CA =
  • 7.79 cm
  • 5.79 cm
  • 15.79 cm
  • 13.79 cm
  • 10.79 cm
Question 9
9.
In an isosceles triangle △ABC, the corresponding height of the side BC is 16.12 cm and area is 129 sq.cm, then corresponding height of side AB =
  • 11.33 cm
  • 14.33 cm
  • 19.33 cm
  • 17.33 cm
  • 9.33 cm
Question 10
10.
In △PQR, if QR = 19 cm, RP = 10 cm and perimeter = 42 cm, then area of the triangle =
  • 60.79 sq.cm
  • 55.79 sq.cm
  • 65.79 sq.cm
  • 57.79 sq.cm
  • 63.79 sq.cm