CBSE Board Practice

CBSE Grade IX - Heron's Formula
Question 1
1.
In △PQR, if QR = 14 cm, RP = 19 cm and the corresponding height of side QR = 18.15 cm, then area of the triangle =
  • 99.08 sq.cm
  • 152.08 sq.cm
  • 127.08 sq.cm
  • 133.08 sq.cm
  • 111.08 sq.cm
Question 2
2.
In an isosceles triangle △ABC, if base BC = 15 cm and the corresponding height is 17.46 cm, then side CA =
  • 24.00 cm
  • 22.00 cm
  • 19.00 cm
  • 14.00 cm
  • 16.00 cm
Question 3
3.
In an isosceles triangle △ABC, if base BC = 15 cm and area is 88.66 sq.cm, then side CA =
  • 9.00 cm
  • 11.00 cm
  • 19.00 cm
  • 14.00 cm
  • 17.00 cm
Question 4
4.
A farmer has a piece of land in the shape of a rhombus. He decided to divide the land into two equal parts such that both his son and daughter could work on the land to produce different crops. If the perimeter of the land is 480.00 m and one of the diagonals is 110 m, how much area will each get for their crops?
  • 5725.95 sq.m
  • 6095.95 sq.m
  • 5815.95 sq.m
  • 5865.95 sq.m
  • 5925.95 sq.m
Question 5
5.
In an isosceles triangle △ABC, if base BC = 19 cm and area is 29.66 sq.cm, then corresponding height of side CA =
  • 7.93 cm
  • 6.93 cm
  • 5.93 cm
  • 3.93 cm
  • 4.93 cm
Question 6
6.
In an isosceles triangle △ABC, if BC = 12 cm, CA = AB and perimeter is 34 cm, then corresponding height of side AB =
  • 13.06 cm
  • 5.06 cm
  • 10.06 cm
  • 7.06 cm
  • 15.06 cm
Question 7
7.
Manisha has a triangular field with sides 70 m, 150 m and 100 m. She wanted to grow brinjals and radish. She divided the field into two parts by joining the mid-point of the longest side to the opposite vertex, and grew brinjals in one part and radish in the other part. How much area has been used for radish.
  • 1229.69 sq.m
  • 1469.69 sq.m
  • 1309.69 sq.m
  • 1649.69 sq.m
  • 1639.69 sq.m
Question 8
8.
In an isosceles triangle △ABC, if BC = 12 cm, AB = CA = 18 cm, then corresponding height of side AB =
  • 14.31 cm
  • 11.31 cm
  • 16.31 cm
  • 8.31 cm
  • 6.31 cm
Question 9
9.
In an isosceles triangle △ABC, if base BC = 19 cm and the corresponding height is 14.1 cm, then side AB =
  • 12.00 cm
  • 22.00 cm
  • 20.00 cm
  • 14.00 cm
  • 17.00 cm
Question 10
10.
A triangular park has sides 150 m, 160 m and 170 m. A gardener has to put a fence all around it and also plant grass inside. Find the cost of fencing it with barbed wire at the rate of ₹34 per metre leaving a space of 5 m wide for the gate on one side.
  • ₹16150.00
  • ₹16650.00
  • ₹18550.00
  • ₹14850.00