CBSE Board Practice

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CBSE Grade X - Triangles

Question 1

1.	In the given figure, if AB ∥ CD then
	△EBA ∼ △EDC △ABE ∼ △DCE △ABE ∼ △EDC △EAB ∼ △ECD △ABE ∼ △ECD

Question 2

2.	In the given figure, △ACB is right-angled at C . P is the mid-point of AC and Q is the mid-point of BC . Which of the following cases are true?
	a) 4 AQ 2 = 4 BC 2 + AC 2 b) 4 AQ 2 = 4 AC 2 + BC 2 c) 4 ( AQ 2 + BP 2 ) = 5 AB 2 d) 4 BP 2 = 4 BC 2 + AC 2 e) 4 BP 2 = 4 AC 2 + BC 2
	{a,e,d} {b,c,d} {a,b,c} {e,c} {a,b}

Question 3

3.	In an equilateral triangle ABC, the side BC is trisected at D. Then
	7 AD 2 = 3 AB 2 9 AD 2 = 7 AB 2 7 AD 2 = 9 AB 2 3 AD 2 = 7 AB 2

Question 4

4.	In the given figure, △ABC ∼ △PQR and BC = 11 cm , QR = 15.4 cm and AD = 11.86 cm , find the area of the △PQR
	128.87 sq.cm 129.87 sq.cm 127.87 sq.cm 126.87 sq.cm 125.87 sq.cm

Question 5

5.	In the given figure, the altitudes MH and IN of △GHI meet at L. △LHI ∼
	△LNM △MIL △NHL △NHI △MIH

Question 6

6.	From the given figure and values, find x
	( -3 , 37 ) ( 38 , -5 ) ( 36 , -4 ) ( 35 , -5 ) ( 35 , -6 )

Question 7

7.	In the given figure, in △GHI, 'O' is a point inside the triangle. OJ ⟂ HI, OK ⟂ GI and OL ⟂ GH. Then
	GL 2 + HJ 2 + IK 2 = GH 2 + JI 2 + IG 2 − HL 2 − IJ 2 − KG 2 GL 2 + HJ 2 + IK 2 = OG 2 + OH 2 + OI 2 − OJ 2 − OK 2 − OL 2 GL 2 + HJ 2 + IK 2 = OG 2 + OH 2 + OI 2 + OJ 2 + OK 2 + OL 2 GL 2 + HJ 2 + IK 2 = OL 2 + OK 2 + OJ 2

Question 8

8.	In the given figure, the altitudes QB and CR of △ABC meet at P. ∠BPR  =
	∠QPC ∠RBP ∠CQP ∠PRB ∠PCQ

Question 9

9.	The altitude and area of an equilateral triangle of side 'a' is
	√ 3 a, 1 2 √ 3 a 2 1 2 √ 3 a, 1 4 √ 3 a 2 √ 3 a, 1 2 √ 3 a 1 2 √ 3 a, 1 2 √ 3 a 2

Question 10

10.	In the given figure, CE is the angular bisector of ∠C & ∠E BC = 20 cm , CD = 20 cm and DE = 20 cm . Find EB
	21.00 cm 20.00 cm 19.00 cm 22.00 cm 18.00 cm

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