CBSE Board Practice

Class VI Class VII Class VIII Class IX Class X
CBSE Grade X - Coordinate Geometry
Question 1
1.
    • One end of the diameter of a circle is
    • (
      2
      ,
      0
      )
    • .
    • If the centre is
    • (
      (
      −
      2
      )
      ,
      7
      2
      )
    • ,
    • find the other end of the diameter
  • (
    (
    −
    8
    )
    ,
    5
    )
  • (
    (
    −
    6
    )
    ,
    7
    )
  • (
    (
    −
    4
    )
    ,
    9
    )
  • (
    (
    −
    7
    )
    ,
    8
    )
  • (
    (
    −
    5
    )
    ,
    6
    )
Question 2
2.
    • Find the coordinates of the vertices of the triangle,
    • the mid points of whose sides are
    • (
      1
      2
      ,
      5
      2
      )
    • ,
    • (
      6
      ,
      (
      −
      1
      2
      )
      )
    • and
    • (
      1
      2
      ,
      4
      )
    • (
      (
      −
      5
      )
      ,
      7
      )
    • ,
    • (
      6
      ,
      (
      −
      2
      )
      )
    • ,
    • (
      6
      ,
      1
      )
    • (
      (
      −
      5
      )
      ,
      7
      )
    • ,
    • (
      6
      ,
      (
      −
      2
      )
      )
    • ,
    • (
      4
      ,
      (
      −
      1
      )
      )
    • (
      (
      −
      5
      )
      ,
      7
      )
    • ,
    • (
      8
      ,
      0
      )
    • ,
    • (
      6
      ,
      1
      )
    • (
      (
      −
      6
      )
      ,
      8
      )
    • ,
    • (
      6
      ,
      (
      −
      2
      )
      )
    • ,
    • (
      6
      ,
      1
      )
    • (
      (
      −
      5
      )
      ,
      7
      )
    • ,
    • (
      6
      ,
      (
      −
      2
      )
      )
    • ,
    • (
      7
      ,
      0
      )
Question 3
3.
    • The line
    • (
      8
      x
      +
      2
      y
      −
      16
      		)
      =
      0
    • bisects which of the following pairs of points?
    • (
      (
      −
      2
      )
      ,
      (
      −
      1
      )
      )
    • ,
    • (
      5
      ,
      2
      )
    • (
      (
      −
      4
      )
      ,
      (
      −
      3
      )
      )
    • ,
    • (
      6
      ,
      1
      )
    • (
      (
      −
      1
      )
      ,
      (
      −
      2
      )
      )
    • ,
    • (
      6
      ,
      1
      )
    • (
      (
      −
      2
      )
      ,
      (
      −
      1
      )
      )
    • ,
    • (
      6
      ,
      1
      )
    • (
      0
      ,
      1
      )
    • ,
    • (
      6
      ,
      1
      )
Question 4
4.
    • Find the value of k such that the points
    • (
      (
      −
      6
      )
      ,
      (
      −
      1
      )
      )
    • ,
    • (
      (
      −
      6
      )
      ,
      1
      )
    • and
    • (-6,k)
    • are collinear
  • 5
  • 1
  • 4
  • 7
  • 3
Question 5
5.
    • (
      (
      −
      4
      )
      ,
      (
      −
      8
      )
      )
    • ,
    • (
      3
      ,
      (
      −
      4
      )
      )
    • and
    • (
      (
      −
      6
      )
      ,
      (
      −
      8
      )
      )
    • are the vertices of triangle ABC.
    • Find the equation of the median of the triangle through vertex C
  • (
    −
    2
    x
    +
    5
    2
    y
    +
    12
    		)
    =
    0
  • (
    −
    2
    x
    +
    11
    2
    y
    +
    32
    		)
    =
    0
  • (
    −
    2
    x
    +
    13
    2
    y
    +
    32
    		)
    =
    0
  • (
    4
    x
    −
    8
    y
    −
    44
    		)
    =
    0
  • (
    −
    2
    x
    +
    9
    2
    y
    +
    32
    		)
    =
    0
Question 6
6.
    • Find the perimeter of the triangle formed by the points
    • (
      7
      ,
      (
      −
      4
      )
      )
    • ,
    • (
      5
      ,
      7
      )
    • and
    • (
      (
      −
      7
      )
      ,
      4
      )
  • (
    5

    √

    5
    +
    3

    √

    15
    +
    2

    √

    65
    )
  • (
    5

    √

    5
    +
    3

    √

    17
    +
    130
    )
  • (
    5

    √

    5
    +
    3

    √

    17
    +
    2

    √

    65
    )
  • (
    5

    √

    5
    +
    3

    √

    19
    +
    2

    √

    65
    )
  • (
    5

    √

    5
    +
    3

    √

    17
    +
    2
    4
    √

    65
    )
Question 7
7.
    • The mid-point of the join of points
    • (
      1
      ,
      (
      −
      8
      )
      )
    • and
    • (
      2
      ,
      (
      −
      1
      )
      )
    • is
  • (
    5
    2
    ,
    (
    −
    11
    2
    )
    )
  • (
    1
    2
    ,
    (
    −
    7
    2
    )
    )
  • (
    3
    2
    ,
    (
    −
    9
    2
    )
    )
  • (
    (
    −
    1
    2
    )
    ,
    (
    −
    13
    2
    )
    )
  • (
    7
    2
    ,
    (
    −
    5
    2
    )
    )
Question 8
8.
A point lies on positive side of x-axis at a distance of 1 units from y-axis. What are the coordinates of the point?
  • (
    0
    ,
    1
    )
  • (
    1
    ,
    0
    )
  • (
    (
    −
    1
    )
    ,
    0
    )
  • (
    0
    ,
    (
    −
    1
    )
    )
Question 9
9.
    • The points
    • (
      (
      −
      2
      )
      ,
      (
      −
      1
      )
      )
    • ,
    • (
      1
      ,
      3
      )
    • and
    • (
      5
      ,
      0
      )
    • represent
  • right angle triangle
  • isosceles right angled triangle
  • equilateral triangle
  • collinear points
  • scalene triangle
Question 10
10.
    • Find the relation between x and y such that the point P
    • (
      x
      ,
      y
      )
    • is equidistant from points
    • (
      (
      −
      1
      )
      ,
      (
      −
      2
      )
      )
    • and
    • (
      (
      −
      3
      )
      ,
      (
      −
      1
      )
      )
  • (
    −
    6
    x
    +
    7
    y
    +
    8
    		)
    =
    0
  • (
    −
    4
    x
    +
    5
    y
    −
    5
    		)
    =
    0
  • (
    −
    6
    x
    +
    5
    y
    +
    8
    		)
    =
    0
  • (
    −
    4
    x
    +
    2
    y
    −
    5
    		)
    =
    0
  • (
    −
    5
    x
    +
    2
    y
    −
    5
    		)
    =
    0