EduSahara™ Worksheet
Name : Chapter Based Worksheet
Chapter : Trigonometry
Grade : SSC Grade X
License : Non Commercial Use
Question
1
1.
sin
15°
cos
75°
+
cos
15°
sin
75°
sin
30°
cos
60°
+
cos
30°
sin
60°
=
(i)
2
(ii)
undefined
(iii)
0
(iv)
-1
(v)
1
Question
2
2.
Express
sec
θ
in terms of
tan
θ
(i)
1
tan
θ
(ii)
tan
θ
√
1
+
tan
2
θ
(iii)
√
1
+
tan
2
θ
(iv)
√
1
+
tan
2
θ
tan
θ
(v)
1
√
1
+
tan
2
θ
Question
3
3.
In the given figure, △GIH is right angled at H. If GH = 25 cm and ∠I = 60°, find IJ
(i)
25
6
√
3
cm
(ii)
25
6
cm
(iii)
25
2
cm
(iv)
25
6
√
18
cm
(v)
25
4
√
2
cm
Question
4
4.
Find the value of
(
1
+
tan
θ
+
sec
θ
)
(
1
+
cot
θ
−
cosec
θ
)
(i)
(-1)
(ii)
2
(iii)
1
(iv)
3
(v)
5
Question
5
5.
Which of the following are true?
a)
sec
2
θ
+
tan
2
θ
=
1
,
0 ≤ θ ≤ 90°
b)
sin
2
θ
−
cos
2
θ
=
1
,
0 ≤ θ ≤ 90°
c)
sec
2
θ
−
tan
2
θ
=
1
,
0 ≤ θ ≤ 90°
d)
sin
2
θ
+
cos
2
θ
=
1
,
0 ≤ θ ≤ 90°
e)
cosec
2
θ
+
cot
2
θ
=
1
,
0 ≤ θ ≤ 90°
f)
cosec
2
θ
−
cot
2
θ
=
1
,
0 ≤ θ ≤ 90°
(i)
{c,d,f}
(ii)
{a,c}
(iii)
{b,c,d}
(iv)
{e,a,f}
(v)
{b,d}
Question
6
6.
Express
cos
θ
in terms of
cot
θ
(i)
cot
θ
√
1
+
cot
2
θ
(ii)
1
√
1
+
cot
2
θ
(iii)
√
1
+
cot
2
θ
(iv)
1
cot
θ
(v)
√
1
+
cot
2
θ
cot
θ
Question
7
7.
Express
tan
50°
in terms of
sin
50°
(i)
1
√
1
−
sin
2
50°
(ii)
√
1
−
sin
2
50°
sin
50°
(iii)
√
1
−
sin
2
50°
(iv)
sin
50°
√
1
−
sin
2
50°
(v)
1
sin
50°
Question
8
8.
Given that
17
sin
θ
=
8
, find
sec
θ
(i)
15
8
(ii)
15
17
(iii)
17
8
(iv)
17
15
(v)
8
15
Question
9
9.
sec
E
=
(i)
1
cot
E
(ii)
1
cos
E
(iii)
1
cosec
E
(iv)
1
tan
E
(v)
1
sin
E
Question
10
10.
In the given figure, △ABC is a right angle triangle with ∠C = 90° and BC = 14 cm. R is the mid-point of AC. Find RC
(i)
21
cm
(ii)
21
2
√
2
cm
(iii)
7
√
3
cm
(iv)
7
cm
(v)
7
√
18
cm
Question
11
11.
In the given figure,
tan
H
=
(i)
7
2
(ii)
35
12
(iii)
11
4
(iv)
37
12
(v)
5
2
Question
12
12.
Given that
3
cosec
θ
=
5
, find
tan
θ
(i)
4
5
(ii)
3
5
(iii)
5
4
(iv)
4
3
(v)
3
4
Question
13
13.
In the given figure,
sec
M
=
(i)
MN
MO
(ii)
ON
OM
(iii)
PN
ON
(iv)
NM
OM
(v)
MO
MN
Question
14
14.
Given that
8
cot
θ
=
15
, find
sec
θ
(i)
15
17
(ii)
8
15
(iii)
17
8
(iv)
8
17
(v)
17
15
Question
15
15.
In the given figure,
cot
N
=
(i)
MN
NL
(ii)
NL
LM
(iii)
ON
NM
(iv)
MN
LM
(v)
LN
NM
Question
16
16.
cosec
H
=
(i)
1
sin
H
(ii)
1
sec
H
(iii)
1
cot
H
(iv)
1
cos
H
(v)
1
tan
H
Question
17
17.
sin
H
=
(i)
1
cos
H
(ii)
1
cosec
H
(iii)
1
tan
H
(iv)
1
sec
H
(v)
1
cot
H
Question
18
18.
Express
cosec
35°
in terms of
cos
35°
(i)
√
1
−
cos
2
35°
(ii)
√
1
−
cos
2
35°
cos
35°
(iii)
1
√
1
−
cos
2
35°
(iv)
cos
35°
√
1
−
cos
2
35°
(v)
1
cos
35°
Question
19
19.
Given
cot
P
=
12
5
,
find
cosec
P
(i)
13
5
(ii)
13
12
(iii)
5
13
(iv)
12
13
(v)
5
12
Question
20
20.
In the given figure,
cos
A
=
(i)
CA
BA
(ii)
CB
DB
(iii)
AB
AC
(iv)
CA
CB
(v)
AC
AB
Question
21
21.
Given that
13
cos
θ
=
12
, find
cosec
θ
(i)
5
12
(ii)
5
13
(iii)
13
12
(iv)
13
5
(v)
12
5
Question
22
22.
Given
tan
H
=
8
15
,
find
cos
H
(i)
17
15
(ii)
15
17
(iii)
8
17
(iv)
17
8
(v)
15
8
Question
23
23.
Given
sec
A
=
17
15
,
find
sin
A
(i)
8
15
(ii)
15
8
(iii)
17
8
(iv)
8
17
(v)
15
17
Question
24
24.
tan
11°
cot
41°
cot
79°
tan
49°
=
(i)
tan
41°
(ii)
tan
11°
(iii)
1
(iv)
0
(v)
-1
Question
25
25.
Express
cosec
θ
in terms of
sin
θ
(i)
√
1
−
sin
2
θ
(ii)
1
√
1
−
sin
2
θ
(iii)
√
1
−
sin
2
θ
sin
θ
(iv)
1
sin
θ
(v)
sin
θ
√
1
−
sin
2
θ
Assignment Key
1) (v)
2) (iii)
3) (i)
4) (ii)
5) (i)
6) (i)
7) (iv)
8) (iv)
9) (ii)
10) (iii)
11) (ii)
12) (v)
13) (v)
14) (v)
15) (iv)
16) (i)
17) (ii)
18) (iii)
19) (i)
20) (iii)
21) (iv)
22) (ii)
23) (iv)
24) (iii)
25) (iv)
